1.) A Small electronic store has begun to advertise in the local newspaper. Before Advertising, the long term average weekly sales were $9820. A random sample of 50 weeks while the newspaper ads were running gave a sample mean weekly sale of X = $10,960. Does this indicate that the population mean weekly sales is now more than $9,820? Test at 5% leval of significance. Assume = $1580.A.) Sate the null and alternate hypotheses. B.) Compute the z or t value of the sample test statistic. t = 0.86, z= 0.73, t = 0.73, z = 0.86, z = -0.86. C.) Find the critical value. z = +2.58. Z = -2.33, Z = +1.96, T = – 1.645. T = +2.58 D.) Based on your answers for parts A – C what is your conculsion? Do not reject, Reject H, Cannot determine, The items in the store cost less than $5, The items in the store do not cost less than $5.2.) A large furiture store has begun a new ad campaign on local television, Before the campaign, the long term average daily sales were $24,819. A random sample of 40 days during the new ad campaign gave a sample mean daily sale of x = $25,910. Does this indicate that the population mean daily sales is now more than $24,819? Use a 1% level of significance. Assume = $1917.A.) State the null and alternate hypotheses. B.) Compute the z or t value of the sample test statistic. C.) Based on your answers for parts A – B, what is your conclusion.3.) A new bus route has been established between downtown Denver and Englewood, a suburb of Denver. Dan has taken the bus to work for many years. For the old bus route, he knows from long experience that the man waiting time between buses at his shop was = 18.3 minutes. However, A random sample standard deciation s = 6.2 minutes. Does this indicate that the population mean waiting time for the new route is different from what it used to be? Use a = 0.05. Assume X is normally distributed.A.) State the null and alternate hypotheses. B.) Computer z or t of the sample test statistic. C.) Based on your answers for parts A – B what is your conclusion?4.) The State Fish and Game Division claims that 75% of the fish in Homestead Creek are Rainbow Trout. however, the local fishing club caught (and released) 189 fish one weekend, and found that 125 were Rainbow Trout. The other fish were Brook Trout, Brown Trout, and so on. Does this indicate that the perventage of Rainbow Trout in Homestead Creek is less than 75%? Use a = 0.01A.) State the null and alternate hypoteses. B.) Computer z or t value of the sample test statistic. C.) Based on your answers for parts A – B what is your conclusion?5.) Long term experience showed that after a type of eye surgery it took a mean of u = 5.3 days, recovery time in a hospital. However, a random sample of 32 patients wish this type of eye surgery, were recently treated as outpatients during the recovery. The sample mean recovery time was x = 4.2 days. Does this indicate that the mean recovery time for outpatients is less than the time for those recovering in the hospital? Use a 1% level of significance. Assume = 1.9 Days.A.) State the null and alternate hypotheses. B.) Computer the z or t value of the sample test statistic. C.) Based on your answers for parts A – B, what is your conclusion.6.) How long go new batteries last on a camping trip? A random sample of n = 42 small camp flashlights were installed with brand I batteries and left on until the batteries failed. The sample mean lifetime was 1x = 9.8 hours. Another random sample of n = 38 small flashlights of the same model were installed with brand II batteries and left on until the batteries failed. The sample mean of lifetimes was 2X = 8.1 hours. Historical data suggests 1 =2.2 hours and 2 = 3.5 hours.A.) Find a 90% confidence interval for the population difference u1 – u2 of lifetimes for these batteries. B.) Does the confidence interval of part (A) contrain all positive, all negative, or both positive and negative numbers? What deos this tell you about the mean life of battery I compared to battery II?7.) Two pain relief drugs being considered. A random sample of 8 doses of the first drug showed that the average amount of time required before the drug was absorbed into the blood stream was 1x = 24 miniutes with standard deviation S1= 3 minutes. For the second drug, a random sample of 10 doses showed the average time required for absorption was 2X = 29 minutes with a standard deviation S2 = 4.9 minutes. Assume the absorption times follow a normal distribution.A.) Find a 90% confidence interval for the difference in average absortion time for the two drugs. Does it apperar that one drug is absorbed faster than the other (at the 90% level)? Explain.