population proportion is 18.3%.B) Reject the null hypothesis at the 5% significance level and the notion that the true population proportion is 18.3%.

1) According to the US Census Bureau, 18.3% of Americans age 18 to 24 were covered by government health insurance in 2009. Suppose that, this year, a random sample of 200 Americans yields 48 who are covered by government health insurance. Test whether the proportion of Americans age 18 to 24 that are covered by government health insurance is different from the 2009 proportion. Use a level of significance of 5%.1a) State the null and alternative hypotheses. (Pick the right answer)A) Ho: p = 0.183Ha: p > 0.183B) Ho: p = 0.24Ha: p < 0.24C) Ho: p = 0.24Ha: p > 0.24D) Ho: p = 0.183Ha: p < 0.183E) Ho: p = 0.183Ha: p != 0.183 (!= means not equal to)F) Ho: p = 0.24Ha: p != 0.24 (!= means not equal to)1b) p_hat = ______ (Your answer should be in decimal form.)1c) Find the P-value. If completing the calculations by hand, make sure you use as many decimals as possible for intermediate calculations, especially the standard error.P-Value = _____ (Round to three decimal places.)1d) Based on the p-value calculated in the previous question, state your conclusion. (Pick the right answer)A) Fail to reject the null hypothesis at the 5% significance level since there is not enough evidence to suggest this sample did not come from a population where the population proportion is 18.3%.B) Reject the null hypothesis at the 5% significance level and the notion that the true population proportion is 18.3%.